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<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>A transient equivalence between Aldous-Broder and Wilson's algorithms and a two-stage framework for generating uniform spanning trees · HackerPapers discussions</title><link>https://hackerpaper.kaipfister.de/p/2206.12378/</link><description>Collected HN comments and submissions linking this paper.</description><language>en</language><lastBuildDate>Mon, 02 Nov 2026 11:16:22 GMT</lastBuildDate><atom:link href="https://hackerpaper.kaipfister.de/p/2206.12378/feed.xml" rel="self" type="application/rss+xml" /><item><title>A transient equivalence between Aldous-Broder and Wilson's algorithms and a two-stage framework for generating uniform spanning trees — mentioned by Arcorann</title><link>https://news.ycombinator.com/item?id=41343766</link><guid isPermaLink="false">urn:hackerpapers:mention:2206.12378:41343766</guid><pubDate>Sun, 25 Aug 2024 02:14:51 GMT</pubDate><description>&lt;p&gt;&amp;gt; I also read that starting with Aldous Broder and then switching to Wilson&amp;#x27;s Algorithm (reasoning: Aldous Broder is slow at the end, Wilson&amp;#x27;s Algorithm is slow at the start) is faster than either. However, I haven&amp;#x27;t seen proof that this combination still results in a uniform spanning tree (where all possible mazes have equal probability). I did some searching, and the paper at [1] (2022) studies the problem. Based on the paper, a naive combination of the two algorithms can generate uniform spanning trees on complete graphs, but more work is needed for arbitrary graphs. [2] apparently cites…&lt;/p&gt;&lt;p&gt;&lt;a href="https://hackerpaper.kaipfister.de/p/2206.12378/"&gt;Paper and discussion history&lt;/a&gt;. A mention is not an endorsement.&lt;/p&gt;</description><category>math.CO</category></item></channel></rss>
