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arXiv:1612.05833math.LO

Borel Circle Squaring

Andrew S. Marks, Spencer T. Unger

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Abstract

We give a completely constructive solution to Tarski's circle squaring problem. More generally, we prove a Borel version of an equidecomposition theorem due to Laczkovich. If $k \geq 1$ and $A, B \subseteq \mathbb{R}^k$ are bounded Borel sets with the same positive Lebesgue measure whose boundaries have upper Minkowski dimension less than $k$, then $A$ and $B$ are equidecomposable by translations using Borel pieces. This answers a question of Wagon. Our proof uses ideas from the study of flows in graphs, and a recent result of Gao, Jackson, Krohne, and Seward on special types of witnesses to the hyperfiniteness of free Borel actions of $\mathbb{Z}^d$.

arXiv comments
Minor typos corrected
Journal reference
Ann. of Math. 186 (2017), 581-605
DOI
doi:10.4007/annals.2017.186.2.4
Subjects
math.LOLogic math.COCombinatorics math.DSDynamical Systems math.MGMetric Geometry

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    • It’s not obvious because, as stated, it’s wrong: https://arxiv.org/abs/1612.05833 You can prove that the disk and the square are not scissors-congruent, based on a convexity invariant, but if you allow more exotic dissections you can construct an equidecomposition.

      intuitionistView on HNParent context

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