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arXiv:1410.2031cs.ET

A Complementary Resistive Switch-based Crossbar Array Adder

A. Siemon, S. Menzel, R. Waser, E. Linn

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Abstract

Redox-based resistive switching devices (ReRAM) are an emerging class of non-volatile storage elements suited for nanoscale memory applications. In terms of logic operations, ReRAM devices were suggested to be used as programmable interconnects, large-scale look-up tables or for sequential logic operations. However, without additional selector devices these approaches are not suited for use in large scale nanocrossbar memory arrays, which is the preferred architecture for ReRAM devices due to the minimum area consumption. To overcome this issue for the sequential logic approach, we recently introduced a novel concept, which is suited for passive crossbar arrays using complementary resistive switches (CRSs). CRS cells offer two high resistive storage states, and thus, parasitic sneak currents are efficiently avoided. However, until now the CRS-based logic-in-memory approach was only shown to be able to perform basic Boolean logic operations using a single CRS cell. In this paper, we introduce two multi-bit adder schemes using the CRS-based logic-in-memory approach. We proof the concepts by means of SPICE simulations using a dynamical memristive device model of a ReRAM cell. Finally, we show the advantages of our novel adder concept in terms of step count and number of devices in comparison to a recently published adder approach, which applies the conventional ReRAM-based sequential logic concept introduced by Borghetti et al.

arXiv comments
12 pages, accepted for IEEE Journal on Emerging and Selected Topics in Circuits and Systems (JETCAS), issue on Computing in Emerging Technologies
Journal reference
DOI
doi:10.1109/JETCAS.2015.2398217
Subjects
cs.ETEmerging Technologies

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    • Based on the diagram this does matmul like a resistive crossbar array (something like https://arxiv.org/pdf/1410.2031.pdf). Talked about this in a ‘neuroprocessor’ class I took at uni. It’s practically ‘free’ since you perform multiplication by applying resistance to a current…

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