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<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>The Binomial Coefficient for Negative Arguments · HackerPapers discussions</title><link>https://hackerpaper.kaipfister.de/p/1105.3689/</link><description>Collected HN comments and submissions linking this paper.</description><language>en</language><lastBuildDate>Mon, 02 Nov 2026 11:16:22 GMT</lastBuildDate><atom:link href="https://hackerpaper.kaipfister.de/p/1105.3689/feed.xml" rel="self" type="application/rss+xml" /><item><title>The Binomial Coefficient for Negative Arguments — mentioned by tromp</title><link>https://news.ycombinator.com/item?id=36013588</link><guid isPermaLink="false">urn:hackerpapers:mention:1105.3689:36013588</guid><pubDate>Sat, 20 May 2023 16:59:39 GMT</pubDate><description>&lt;p&gt;If Knuth is correct then I wonder how this paper https://arxiv.org/pdf/1105.3689.pdf cited by 32, proves Theorem 2.1 that gives Binomial[-1,-1] = Binomial[0,0] = 1. What exactly is the assumption on which they differ? Whatever value you set this coeficient to, it&amp;#x27;s clear that not all of the familiar binomial properties 1. (n k) = (n-1 k-1) + (n-1 k) 2. (n 0) = 1 3. (n k) = (n n-k) can remain true, as 1. gives 1 = (0 0) = (-1 -1) + (-1 0), and 2. makes this sum 0 + 1, while 3. would make it 1/2 + 1/2.&lt;/p&gt;&lt;p&gt;&lt;a href="https://hackerpaper.kaipfister.de/p/1105.3689/"&gt;Paper and discussion history&lt;/a&gt;. A mention is not an endorsement.&lt;/p&gt;</description><category>math.CO</category></item></channel></rss>
